Mathematics · Height and Distance
A tower PQ stands on a horizontal ground with base Q on the ground. The point R divides the tower into two parts such that QR = 15 m. If from a point A on the ground the angle of elevation of R is 60° and the part PR of the tower subtends an angle of 15° at A, then the height of the tower is:
- 110(2√3 + 1) m
- 210(√3 + 1) m
- 35(√3 + 3) m
- 45(2√3 + 3) m✓
Correct answer
5(2√3 + 3) m
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