Mathematics · Errors in Measurement
A student conducts an experiment to determine the acceleration due to gravity using the formula gT24π2 = l. The length of the pendulum (l ≈ 1 m) has an error denoted by Δl. To measure the time period T, the student records the total time for n oscillations using a stopwatch. The stopwatch has a least count error ΔTc, and the student also makes a human error ΔTh = 0.1 s. The amplitude of oscillation is A. Which of the following options gives the most accurate measurement of g?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Δl = 1 mm, ΔTc = 0.1 s, n = 50, A = 1 mm✓
- 2Δl = 5 mm, ΔTc = 0.1 s, n = 20, A = 1 mm
- 3Δl = 5 mm, ΔTc = 0.2 s, n = 20, A = 5 mm
- 4Δl = 5 mm, ΔTc = 0.2 s, n = 10, A = 5 mm
Correct answer
Δl = 1 mm, ΔTc = 0.1 s, n = 50, A = 1 mm
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