Physics · Gravitation
A solid sphere of radius R gravitationally attracts a particle placed at a distance of 3R from its centre with a force F1. Now, a spherical cavity of radius R2 is made in the sphere such that it touches the surface, and the force becomes F2. The value of F1 : F2 is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 125 : 36
- 236 : 25
- 350 : 41✓
- 441 : 50
Correct answer
50 : 41
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Physics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Gravitation MCQs →Want more practice questions on Gravitation?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Physics · Gravitation