Physics · Laws of Motion
A shell of mass m is at rest initially. It explodes into three fragments having masses in the ratio 2 : 2 : 1. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, the speed of the third (lighter) fragment is:
- 12√2 v✓
- 2√2 v
- 3v
- 43√2 v
Correct answer
2√2 v
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