Physics · Electric Circuits
A series RL circuit has R = 5 Ω and L = 1 H. The circuit is initially under a steady-state condition with a current of 2 A. If the source is bypassed at t = 0, the current i(t) for t ≥ 0 will be:
- 12e 5t A
- 21 + 2e -5t A
- 31 - 2e -5t A
- 42e -5t A✓
Correct answer
2e -5t A
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