Physics · Electrostatics - Electric Field
A rod AB is bent into a 120° circular arc of radius R. A charge (-Q) is uniformly distributed over the rod AB. What is the electric field vector E at the center of curvature O (assuming symmetry along the x-axis)?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 13√3 Q16π2 ε0 R2 î
- 2- 3√3 Q8π2 ε0 R2 î
- 33√3 Q8π ε0 R2 î
- 43√3 Q8π2 ε0 R2 î✓
Correct answer
3√3 Q8π2 ε0 R2 î
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