Physics · AC Circuits
A pure capacitor of reactance 5 Ω is connected across an AC source of v(t) = 10 sin(50t − 10°) V. The current through the circuit is given by ______.
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 12500 sin(50t + 80°) A
- 22 sin(50t − 100°) A
- 32500 sin(50t + 100°) A
- 42 sin(50t + 80°) A✓
Correct answer
2 sin(50t + 80°) A
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