Physics · Oscillations
A particle of mass 4 mg is executing simple harmonic motion along the x-axis with an angular frequency of 40 rad/s. If the potential energy of the particle is V(x) = a + bx 2 , where V(x) is in joules and x is in meters, then the value of b is:
- 16400 × 10 -6 J/m 2
- 23200 × 10 -6 J/m 2✓
- 31600 × 10 -6 J/m 2
- 4800 × 10 -6 J/m 2
Correct answer
3200 × 10 -6 J/m 2
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