Physics · Kinematics
A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution. If this particle were projected with the same speed at an angle θ to the horizontal, the maximum height attained by it equals 4R. The angle of projection, θ, is then given by:
- 1θ = sin-1[(π2R / gT2)1/2]
- 2θ = cos-1[(π2R / gT2)1/2]
- 3θ = cos-1[(gT2 / π2R)1/2]
- 4θ = sin-1[(2gT2 / π2R)1/2]✓
Correct answer
θ = sin-1[(2gT2 / π2R)1/2]
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