A particle is executing simple harmonic motion along the X-axis. If at distances x1 and x2 from the mean position, the velocities of the particle are v1 and v2 respectively, the time period of its oscillation is given by:

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Mathematics · Simple Harmonic Motion

Verified Solution4 OptionsUpdated: October 2026👁️1 View

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T = 2π √[ (x22 − x12) / (v12 − v22) ]

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Answer 1

T = 2π √[ (x22 − x12) / (v12 − v22) ]

Answer 2

T = 2π √[ (x22 − x12) / (v12 + v22) ]

Answer 3

T = 2π √[ (x22 + x12) / (v12 + v22) ]

Answer 4

T = 2π √[ (x22 + x12) / (v12 − v22) ]

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