Physics · Motion in a Plane
A particle crossing the origin at time t = 0 moves in the xy-plane with a constant acceleration 'a' in the y-direction. If the equation of the trajectory of the particle is y = bx2 (where b is a constant), then its velocity component in the x-direction is:
- 1√(ba)
- 2√(ab)
- 3√(a2b)✓
- 4√(2ba)
Correct answer
√(a2b)
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