Mathematics · Capacitance Calculations
A parallel-plate capacitor of plate area A and separation d is connected to a battery of voltage V. A dielectric slab of thickness d2 and dielectric constant K fully covering the area is inserted between the plates. What is the new charge on the capacitor?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1(K + 1)ε0AV2d
- 2Kε0AVd(K + 1)
- 32Kε0AVd(K + 1)✓
- 4ε0AVd
Correct answer
2Kε0AVd(K + 1)
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