Physics · Capacitance
A parallel plate capacitor is charged by a battery, and the battery remains connected. A dielectric slab of dielectric constant 'K' is inserted between the plates and then taken out. The final electric field between the plates, compared to its initial value before insertion, will:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1remain the same✓
- 2increase
- 3decrease
- 4become zero
Correct answer
remain the same
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