Physics · Electrostatics
A parallel plate capacitor is charged by a battery, and the battery remains connected. A dielectric slab of constant 'K' is inserted between the plates and then taken out. The electric field between the plates after this process:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1becomes zero
- 2decreases
- 3increases
- 4remains the same✓
Correct answer
remains the same
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