Mathematics · Number System
A natural number has a prime factorization given by n = 2x3y5z, where y and z are such that y + z = 5 and y-1 + z-1 = 56, and y > z. Then the number of odd divisors of n, including 1, is:
- 118
- 211
- 36
- 412✓
Correct answer
12
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