Physics · Classical Mechanics
A massless rod of length l is hinged at the extreme end of a vertical spring whose other end is fixed to the ground. A point mass m is fixed at the other end of the rod. Assume the harmonic motion of the spring is given by h(t) = h 0 (2 + cos(ωt)), where h 0 > l. The angular equation of motion of the mass (confined to the plane) is given by:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1lθ'' - ω 2 h 0 sin(θ)sin(ωt) + gsin(θ) = 0
- 2lθ'' + ω 2 h 0 sin(θ)cos(ωt) - gsin(θ) = 0✓
- 3lθ'' + ω 2 h 0 sin(θ)cos(ωt) - g = 0
- 4lθ'' + ω 2 h 0 sin(θ)sin(ωt) - gIn(θ) = 0
Correct answer
lθ'' + ω 2 h 0 sin(θ)cos(ωt) - gsin(θ) = 0
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