Computer · Surveying
A level is set up at a point 150 m from station A and 100 m from station B. The observed staff readings at A and B are 2.525 m and 1.755 m, respectively. If the combined correction for curvature and refraction to the staff readings at A and B are 0.0015 m and 0.0007 m respectively, what is the true difference in level between A and B?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 10.7692 m✓
- 21.7543 m
- 32.1257 m
- 42.5325 m
Correct answer
0.7692 m
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