Chemistry · Organic Chemistry
A hydrocarbon 'P' (C4H8) on reaction with HCl gives an optically active compound 'Q' (C4H9Cl), which upon reaction with one mole of ammonia yields compound 'R' (C4H11N). 'R' on diazotization followed by hydrolysis gives an alcohol 'S'. Identify P, Q, R, and S from the options below:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1P = But-1-ene, Q = 1-Chlorobutane, R = Butan-1-amine, S = Butan-1-ol
- 2P = But-1-ene, Q = 2-Chlorobutane, R = Butan-2-amine, S = Butan-2-ol✓
- 3P = 2-Methylpropene, Q = 2-Chloro-2-methylpropane, R = 2-Methylpropan-2-amine, S = 2-Methylpropan-2-ol
- 4P = But-2-ene, Q = 2-Chlorobutane, R = Butan-1-amine, S = Butan-2-ol
Correct answer
P = But-1-ene, Q = 2-Chlorobutane, R = Butan-2-amine, S = Butan-2-ol
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