Physics · Mechanical Properties of Fluids
A hydraulic lift in a service station has a large piston 30 cm in diameter and a small piston 3 cm in diameter. The force required on the small piston to lift a load of 2000 kg will be: (g = 10 m/s2)
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 12000 N
- 2600 N
- 3400 N
- 4200 N✓
Correct answer
200 N
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