Physics · Motion in a Straight Line
A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to (where g is the acceleration due to gravity):
- 1t = √(2h/3g)
- 2t = 3.4 √(h/g)✓
- 3t = 1.8 √(h/g)
- 4t = 23 √(h/g)
Correct answer
t = 3.4 √(h/g)
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