Mathematics · Differential Equations
A general solution of the differential equation (ex + e-x)dy + (ex - e-x)dx = 0 is: (where C is an arbitrary constant)
- 1y = ex - e-x + C
- 2y = ex + e-x + C
- 3y = loge|ex - e-x| + C
- 4y = loge|ex + e-x| + C✓
Correct answer
y = loge|ex + e-x| + C
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