Mathematics · Divisibility Rules
A four-digit number abcd is divisible by 11 if the difference between the sum of digits at odd places and the sum of digits at even places is either 0 or a multiple of 11. This condition can be written as: (d + b) - (a + c) = 0 or a multiple of 11. Thus, d + b is equal to which of the following?
- 1a + c or 11 + (a + c)✓
- 22 or 11 + (a + c)
- 3c or 11 + (a + c)
- 4a or 11 + (a + c)
Correct answer
a + c or 11 + (a + c)
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