Physics · Electrostatics
A dielectric slab of thickness d is inserted into a parallel-plate capacitor. The negative plate is located at x = 0 and the positive plate is at x = 3d. The dielectric slab is placed symmetrically between the plates (from x = d to x = 2d). The capacitor is given a charge. As x goes from 0 to 3d, which of the following statement(s) is/are correct?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 1The electric potential increases at first, then decreases, and then increases again.
- 2The electric potential increases continuously.✓
- 3The direction of the electric field reverses inside the dielectric.
- 4The magnitude of the electric field remains the same throughout.
Correct answer
The electric potential increases continuously.
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Physics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Electrostatics MCQs →Want more practice questions on Electrostatics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Physics · Electrostatics