Mathematics · DC Machines
A DC shunt machine develops an induced electromotive force (emf) of 250 V at 1500 rpm. Determine its developed electromagnetic torque and mechanical power for an armature current of 50 A.
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Power = 10.5 kW and Torque = 79.6 Nm
- 2Power = 14.5 kW and Torque = 69.6 Nm
- 3Power = 12.5 kW and Torque = 79.6 Nm✓
- 4Power = 15.5 kW and Torque = 89.6 Nm
Correct answer
Power = 12.5 kW and Torque = 79.6 Nm
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