Physics · Magnetic Fields
A current 'i' flows through an infinitely long solenoid of radius 'r' and 'n' turns per unit length. The magnetic field produced at an axial point deep inside the solenoid is expressed as:
- 1B = (μ0/4π) (n i r)
- 2B = (μ0/4π) (4πni/r)
- 3B = (μ0/4π) (ni/r2)
- 4B = (μ0/4π) (4πni)✓
Correct answer
B = (μ0/4π) (4πni)
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