Computer · Structural Analysis
A continuous beam ABCD has end A fixed, B and C as simple supports, and end D free. The fixed end moments for beam member AB are FEMAB = -19.2 kNm and FEMBA = +28.8 kNm. Given that support A is fixed (θA = 0), the slope-deflection equations for the moments Mab and Mba can be written as:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Mab = 2EIL(2θA + θB) + 28.8 Mba = 2EIL(θA + 2θB) - 19.2
- 2Mab = 2EIL(θA) - 19.2 Mba = 4EIL(θA) + 28.8
- 3Mab = 4EIL(θA) - 19.2 Mba = 2EIL(θA) + 28.8
- 4Mab = 2EIL(θB) - 19.2 Mba = 4EIL(θB) + 28.8✓
Correct answer
Mab = 2EIL(θB) - 19.2 Mba = 4EIL(θB) + 28.8
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