Physics · Electromagnetic Induction
A conducting bar AB of length 'L' is free to slide on two parallel conducting rails connected with resistors R1 on the left and R2 on the right, forming two closed loops. There is a uniform magnetic field vector B pointing perpendicularly outward from the page. When the bar AB moves towards the left at a constant speed vector V, what are the directions of the induced currents I1 (through R1) and I2 (through R2)?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1I1 is in the clockwise direction and I2 is in the counter-clockwise direction
- 2Both I1 and I2 are in the clockwise direction
- 3Both I1 and I2 are in the counter-clockwise direction
- 4I1 is in the counter-clockwise direction and I2 is in the clockwise direction✓
Correct answer
I1 is in the counter-clockwise direction and I2 is in the clockwise direction
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