Physics · Alternating Current
A circuit element 'X' when connected to a peak voltage of 200 V allows a peak current of 5 A to flow, which lags behind the voltage by π2. Another circuit element 'Y' when connected to the same peak voltage allows the same peak current to flow, which is in phase with the voltage. If X and Y are connected in series with the same AC source of peak voltage 200 V, the RMS value of the current through the circuit will be:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 15 A
- 25√2 A✓
- 32.5 A
- 45√2 A
Correct answer
5√2 A
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