Mathematics · Circle
A circle touches both the coordinate axes and the straight line L ≡ 4x + 3y - 6 = 0 in the first quadrant. If this circle lies below the line L = 0, then the equation of that circle is:
- 1x2 + y2 - 6x - y - 9 = 0
- 2x2 + y2 - 6x - 6y + 9 = 0
- 34x2 + 4y2 - 4x - 24y + 1 = 0
- 44x2 + 4y2 - 4x - 4y + 1 = 0✓
Correct answer
4x2 + 4y2 - 4x - 4y + 1 = 0
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