Mathematics · Capacitance Calculation
A capacitive transducer is formed by two parallel plates, each of dimension 200 mm × 100 mm with two dielectrics of εr1 = 5 for 10-mm thickness and εr2 = 4 for 8-mm thickness filling in the gap of 18 mm between them. Considering ε0 = 9 pF/m, the nominal capacitance of this transducer is:
- 122.5 pF
- 245 pF✓
- 390 pF
- 4180 pF
Correct answer
45 pF
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Mathematics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Capacitance Calculation?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Capacitance Calculation