Biology · Biophysics
A canonical Watson-Crick G:C base pair is stabilized by three hydrogen bonds formed between donor (+0.25e) and acceptor (-0.35e) atoms located at an average distance r = 0.29 nm. Assume that the dielectric constant 'D' in the DNA core is 4, and in water is 78.5. Using Coulomb's relation with the modified constant k = 1389 kJ·nm/(mol·e2), which one of the following options correctly represents the total difference in electrostatic interaction energy for all 3 hydrogen bonds when buried in the DNA core versus being fully exposed to the aqueous solvent?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1-5.338 kJ/mol
- 2-99.4 kJ/mol
- 3-104.7 kJ/mol
- 4-298.3 kJ/mol✓
Correct answer
-298.3 kJ/mol
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