Physics · Gravitation
A body is projected vertically upwards from the surface of Earth with a velocity sufficient enough to carry it to infinity (escape velocity). The time taken by it to reach a height h is:
- 1√[Re / (2g)] × [(1 + h/Re)3/2 - 1]
- 2√[2Re / g] × [(1 + h/Re)3/2 - 1]
- 313 √[Re / (2g)] × [(1 + h/Re)3/2 - 1]
- 413 √[2Re / g] × [(1 + h/Re)3/2 - 1]✓
Correct answer
13 √[2Re / g] × [(1 + h/Re)3/2 - 1]
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