Physics · Circular Motion
A bob of mass 'm' is suspended by a light string of length 'L'. It is imparted a minimum horizontal velocity at the lowest point A such that it just completes a half circle, reaching the topmost position B. The ratio of kinetic energies (K.E.)A(K.E.)B is:
- 11 : 5
- 22 : 5
- 35 : 1✓
- 43 : 2
Correct answer
5 : 1
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