Physics · Mechanics
A bead P slides on a frictionless semi-circular string (ACB) in a vertical plane and is at the lowest point C at t = 0, where the horizontal component of its velocity is v. Another bead Q of the same mass as P is projected from point A at t = 0 along a horizontal string AB with a constant speed v. Friction is neglected in both cases. If tP and tQ are the respective times taken by beads P and Q to reach point B, then what is the relation between tP and tQ?
- 1tP = 2tQ
- 2tP = tQ
- 3tP < tQ✓
- 4tP > tQ
Correct answer
tP < tQ
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