Mathematics · Algebraic Identities
a ≠ b के लिए, बीजीय व्यंजक [a2 - b2 + a(a + b)] / [a(a - b) + b(a - b)] का सरलीकृत मान क्या है?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1(a - 2b) / (a + b)
- 2(2a - b) / (a - b)✓
- 3(2a - b) / (a + b)
- 4(a - 2b) / (a - b)
सही उत्तर देखें
(2a - b) / (a - b)
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