Mathematics · Work, Power and Energy
A 60 HP electric motor lifts an elevator with a maximum total load capacity of 2000 kg. If the frictional force on the elevator is 4000 N, the speed of the elevator at full load is close to: (Given 1 HP = 746 W, g = 10 m/s2)
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 12.0 m/s
- 21.7 m/s
- 31.5 m/s
- 41.9 m/s✓
Correct answer
1.9 m/s
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