Mathematics · Electrical Capacitance Network
While checking a faulty AC unit, it is observed that a 40 μF power capacitor is defective. The store room only has capacitors of 25 μF, 30 μF, and 50 μF in stock. How can the unit be operated to achieve an equivalent capacitance of 40 μF using the available stock?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1By connecting two 30 μF capacitors in series and one 25 μF capacitor in parallel to that combination
- 2By connecting two 50 μF capacitors in series and one 25 μF capacitor in parallel to that combination✓
- 3By connecting two 30 μF capacitors in parallel and one 25 μF capacitor in series to that combination
- 4By connecting two 50 μF capacitors in parallel and one 25 μF capacitor in series to that combination
Correct answer
By connecting two 50 μF capacitors in series and one 25 μF capacitor in parallel to that combination
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