Mathematics · Trigonometry
When 0° < θ < 90°, the value of 2 - √cot(θ) + cos(θ)cot(θ) - cos(θ) is equal to:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 12 + sec(θ) - tan(θ)
- 22 - sec(θ) - tan(θ)✓
- 32 - sec(θ) + tan(θ)
- 42 + sec(θ) + tan(θ)
Correct answer
2 - sec(θ) - tan(θ)
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