Physics · Quantum Mechanics
The wave function ψ(x) = A exp(-b2x2/2) (where A and b are real constants) is a normalized eigenfunction of the Schrodinger equation for a particle of mass m and energy E in a one-dimensional potential V(x), such that V(x) = 0 at x = 0. Which of the following relations is correct?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1V = ℏ2b4x2m
- 2V = ℏ2b4x22m✓
- 3E = ℏ2b24m
- 4E = ℏ2b2m
Correct answer
V = ℏ2b4x22m
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