Physics · Molecular Spectroscopy
The vibrational energy for a diatomic molecule is given by G(v) = (v + 1/2)νe − (v + 1/2)2νexe, where νe is the fundamental frequency and xe is the anharmonicity constant. The infrared spectrum of BeO molecule in an excited state shows two transitions at 1078.48 cm−1 and 1062.42 cm−1, identified as transitions between vibrational levels 2 → 3 and 3 → 4, respectively. The νe and νexe (in cm−1) for BeO molecule in this state, respectively, are
- 11078.48 and 8.03
- 21174.84 and 16.06
- 31030.30 and −8.03
- 41126.66 and 8.03✓
Correct answer
1126.66 and 8.03
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