Mathematics · Modern Physics
The minimum frequency of a photon required to break a nucleus of mass 16.008 amu into 4 α particles is ________ × 1020 Hz. [Given: mass of He nucleus = 4.002 amu, 1 amu = 1.66 × 10-27 kg, h = 6.6 × 10-34 J·s and c = 3 × 108 m/s]
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 114.94 × 1019✓
- 214.94 × 1020
- 39 × 1020
- 49 × 1019
Correct answer
14.94 × 1019
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