Physics · Heat Transfer
The Logarithmic Mean Temperature Difference (Δtm) for a heat exchanger is given by which relation? (where Δti and Δto are the temperature differences at inlet and outlet)
- 1Δtm = (Δto - Δti) / loge(Δti/Δto)
- 2Δtm = loge(Δto - Δti) / (Δto/Δti)
- 3Δtm = (Δto - Δti) / loge(Δto/Δti)✓
- 4Δtm = loge(Δto/Δti) / (Δto - Δti)
Correct answer
Δtm = (Δto - Δti) / loge(Δto/Δti)
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