Physics · Classical Mechanics
The Lagrangian for a simple pendulum is given by L = 12ml2θ̇2 - mgl(1 - cosθ). If H is the Hamiltonian of the pendulum, what is the value of dHdt?
- 1-2glpθ sinθ
- 22glpθ sinθ
- 3-glpθ sinθ
- 40✓
Correct answer
0
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