Mathematics · Trigonometric Equations
The general solution of the equation sin2θ secθ + √3 tanθ = 0 is (where n ∈ Z):
- 1θ = n π2
- 2θ = nπ + (-1)n+1 π6
- 3θ = nπ
- 4θ = nπ + (-1)n+1 π3✓
Correct answer
θ = nπ + (-1)n+1 π3
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