Mathematics · AC Circuits
The current i(t) through a 10 Ω resistor in series with an inductance is given by i(t) = 3 + 4 sin(100t + 45°) + 4 sin(300t + 60°) amperes. The RMS value of the current and the power dissipation in the resistor are respectively:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 111 A and 1210 W
- 25 A and 250 W
- 3√41 A and 410 W
- 4√25 A and 250 W✓
Correct answer
√25 A and 250 W
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