Mathematics · Complex Analysis
The complete solution of the complex equation sinh(z + 2πi) = 0 is given by (where k is any integer):
- 1z = iπ(2k+1)2
- 2z = iπ(k + 2i)
- 3z = iπk✓
- 4z = π(4 - 2ki - 1)2
Correct answer
z = iπk
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