Physics · Classical Mechanics
The action corresponding to the motion of a particle in one dimension is given by S = ∫t1t2 dt [ 12mẋ2 - V(x) + αxẍ + βxẋ ] where m is the mass of the particle, α and β are constants, and V(x) is a potential. The position and velocity are held fixed at the end points of the trajectory. The equation of motion of the particle is:
- 1(2α - m)ẍ - dVdx = 0✓
- 2(2α - m)ẍ - βẋ - dVdx = 0
- 3(2α - m)ẍ + βẋ - dVdx = 0
- 4(2α + m)ẍ - dVdx = 0
Correct answer
(2α - m)ẍ - dVdx = 0
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