Mathematics · Statistical Inference
Let X1, X2, ..., Xn be a random sample from an N(θ, 1) distribution, where θ ∈ ℝ is unknown. Let δn be the Bayes estimator of θ under the squared error loss function L(θ, a) = (a - θ)2 and the prior distribution N(1, 2). If 1√n[(2n + 1)δn - 1 - 2nθ] converges in distribution to a random variable Z as n → ∞, then which of the following statements is true?
- 1E(Z2) = 1
- 2E(Z4) = 48
- 3Z follows a standard normal distribution.
- 4δn converges in probability to θ as n → ∞, for all θ ∈ ℝ.✓
Correct answer
δn converges in probability to θ as n → ∞, for all θ ∈ ℝ.
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