Mathematics · Definite Integrals
Let f be a continuous function satisfying ∫0t2 (f(x) + x2) dx = 43t3, ∀ t > 0. Then f( π24 ) is equal to:
- 1π2(1 − π216)✓
- 2−π(1 + π316)
- 3−π2(1 + π216)
- 4π(1 − π316)
Correct answer
π2(1 − π216)
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