Mathematics · Complex Analysis
- 1f(r) = z 0 for all r ∈ ℚ ∩ [1, 2] ⇒ f is the constant function z 0
- 2f(n) = z 0 for all n ∈ ℕ ⇒ f is the constant function z 0
- 3f(1/n) = z 0 for all n ∈ ℕ ⇒ f is the constant function z 0✓
- 4f can take the value z 0 at finitely many points in {1/n | n ∈ ℕ}
Correct answer
f(1/n) = z 0 for all n ∈ ℕ ⇒ f is the constant function z 0
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